Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:02Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-t²) dt = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
411K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
448K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
22K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
459K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
406K
λ = h/p
iħ ∂ψ/∂t = Ĥψ
d/dγ [γ^3] = 3γ^2
CH₄ + 2O₂ → CO₂ + 2H₂O