Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
det| 12 2 ; 2 13 | = 152
438K
det| 6 4 ; 3 7 | = 30
ΔS ≥ 0
1z² + 3z + 2 = 0
7t² + 3t + 1 = 0
det| 8 3 ; 4 9 | = 60
det| 4 8 ; 3 5 | = -4
455K
∇ × E = −∂B/∂t