Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:18Z

10γ² + 4γ + 3 = 0

d/dt [t^3] = 3t^2

460K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

438K

d/dβ [β^11] = 11β^10

∑_{k=1}^{n} k = n(n+1)/2

186K

∂γ/∂θ = 2γ

411K

3x² + 4x + 6 = 0

det| 9 4 ; 1 10 | = 86

448K

det| 3 6 ; 0 4 | = 12

22K

CaCO₃ → CaO + CO₂

11z² + 3z + 4 = 0

459K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∑_{k=1}^{n} k = n(n+1)/2

F = ma