Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

λ = h/p

186K

6t² + 6t + 4 = 0

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

8θ² + 8θ + 6 = 0

22K

F = G m₁m₂ / r²

459K

iħ ∂ψ/∂t = Ĥψ

406K

∫₀^∞ e^(-α²) dα = √π / 2

181K

5φ² + 1φ + 1 = 0

80K

det| 9 4 ; 1 10 | = 86

359K

d/dx [x^3] = 3x^2

455K