Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:34Z

∇²t = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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iħ ∂ψ/∂t = Ĥψ

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det| 6 4 ; 3 7 | = 30

∇²t = 0

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N₂ + 3H₂ ⇌ 2NH₃

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ΔS ≥ 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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8ψ² + 7ψ + 0 = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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