Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:05Z

∇²x = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

∇ × E = −∂B/∂t

264K

det| 3 9 ; 1 4 | = 3

det| 3 7 ; 2 4 | = -2

297K

10ψ² + 5ψ + 0 = 0

252K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

48K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

det| 8 9 ; 4 9 | = 36

\lim_{t\to 0} \frac{\sin t}{t} = 1

377K

6t² + 6t + 4 = 0

299K

det| 7 4 ; 4 8 | = 40

401K

∂β/∂β = 6β

420K

∑_{k=1}^{n} k = n(n+1)/2

109K

F = G m₁m₂ / r²

184K