Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:05Z

∑_{k=1}^{n} k = n(n+1)/2

det| 1 4 ; 3 2 | = -10

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det| 2 8 ; 7 3 | = -50

264K

det| 8 9 ; 3 9 | = 45

det| 4 2 ; 6 5 | = 8

297K

d/dt [t^3] = 3t^2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

PV = nRT

48K

det| 9 4 ; 1 10 | = 86

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det| 2 3 ; 3 3 | = -3

∇²γ = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

401K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

420K