Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

∇²r = 0

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇²z = 0

186K

det| 1 4 ; 3 2 | = -10

411K

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

CH₄ + 2O₂ → CO₂ + 2H₂O

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

∇²ω = 0

406K

iħ ∂ψ/∂t = Ĥψ

181K

det| 8 9 ; 4 9 | = 36

80K

N₂ + 3H₂ ⇌ 2NH₃

359K

8ψ² + 7ψ + 0 = 0

455K