Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:38Z

10y² + 2y + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 4 8 ; 3 5 | = -4

186K

det| 12 1 ; 5 13 | = 151

411K

e^{i\pi} + 1 = 0

d/dt [t^3] = 3t^2

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

459K

8ψ² + 7ψ + 0 = 0

406K

∫₀^∞ e^(-α²) dα = √π / 2

181K

8x² + 2x + 7 = 0

80K