Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

10ψ² + 5ψ + 0 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇²ω = 0

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

10ω² + 7ω + 4 = 0

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

459K

det| 7 8 ; 4 8 | = 24

406K

λ = h/p

\lim_{t\to 0} \frac{\sin t}{t} = 1

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

e^{i\pi} + 1 = 0

359K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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