Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:26Z

∇²x = 0

2n² + 4n + 0 = 0

451K

iħ ∂ψ/∂t = Ĥψ

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det| 3 9 ; 1 4 | = 3

det| 9 5 ; 1 10 | = 85

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det| 8 9 ; 4 9 | = 36

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CaCO₃ → CaO + CO₂

10ω² + 7ω + 4 = 0

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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det| 8 9 ; 4 9 | = 36

\lim_{r\to 0} \frac{\sin r}{r} = 1

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

299K

det| 7 6 ; 6 8 | = 20

N₂ + 3H₂ ⇌ 2NH₃

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8ψ² + 7ψ + 0 = 0

420K

6ω² + 4ω + 4 = 0

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∇ × E = −∂B/∂t

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