Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

∇ × E = −∂B/∂t

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∇²θ = 0

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9ψ² + 4ψ + 2 = 0

∂n/∂θ = 3n

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1θ² + 2θ + 6 = 0

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d/dβ [β^6] = 6β^5

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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8ψ² + 7ψ + 0 = 0

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det| 6 1 ; 4 7 | = 38

d/dt [t^3] = 3t^2

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ΔS ≥ 0

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\frac{6}{5} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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