Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:52Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
d/dβ [β^11] = 11β^10
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
411K
3x² + 4x + 6 = 0
det| 5 6 ; 2 6 | = 18
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
CH₄ + 2O₂ → CO₂ + 2H₂O
181K