Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:36Z
∇²n = 0
det| 7 4 ; 4 8 | = 40
273K
∑_{k=1}^{n} k = n(n+1)/2
263K
9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
139K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
333K
det| 3 6 ; 0 4 | = 12
160K
11γ² + 3γ + 6 = 0