Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:31Z

∇²n = 0

∇ × E = −∂B/∂t

273K

∇²r = 0

263K

9r² + 4r + 1 = 0

F = G m₁m₂ / r²

139K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

det| 7 4 ; 4 8 | = 40

160K

11γ² + 3γ + 6 = 0

iħ ∂ψ/∂t = Ĥψ

439K

e^{i\pi} + 1 = 0

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

∇ × E = −∂B/∂t

297K

∑_{k=1}^{n} k = n(n+1)/2

128K

det| 6 1 ; 3 7 | = 39

\frac{2}{2} \sum_{i=1}^{n} i^{2}

404K

e^{i\pi} + 1 = 0