Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

E = mc²

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-t²) dt = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

448K

∫₀^∞ e^(-θ²) dθ = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

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iħ ∂ψ/∂t = Ĥψ

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