Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:35Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

3z² + 5z + 1 = 0

186K

det| 10 7 ; 3 11 | = 89

411K

4φ² + 6φ + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

det| 3 6 ; 0 4 | = 12

406K

∇²ω = 0

∑_{k=1}^{n} k = n(n+1)/2

181K

9ψ² + 7ψ + 3 = 0

80K

d/dr [r^2] = 2r^1

ΔS ≥ 0

8β² + 5β + 0 = 0