Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:39Z

∑_{k=1}^{n} k = n(n+1)/2

11t² + 9t + 5 = 0

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∇ × E = −∂B/∂t

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e^{i\pi} + 1 = 0

λ = h/p

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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2H₂ + O₂ → 2H₂O

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 10 2 ; 3 11 | = 104

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det| 4 8 ; 0 5 | = 20

\lim_{t\to 0} \frac{\sin t}{t} = 1

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6t² + 6t + 4 = 0

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d/dt [t^3] = 3t^2

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det| 11 9 ; 0 12 | = 132

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∑_{k=1}^{n} k = n(n+1)/2

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8ψ² + 7ψ + 0 = 0

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