Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:17Z

∇²n = 0

e^{i\pi} + 1 = 0

273K

∇²θ = 0

263K

9r² + 4r + 1 = 0

∂γ/∂z = 6γ

139K

det| 7 4 ; 4 8 | = 40

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

160K

11γ² + 3γ + 6 = 0

∇²ω = 0

439K

det| 9 8 ; 3 10 | = 66

413K

∑_{k=1}^{n} k = n(n+1)/2

297K

N₂ + 3H₂ ⇌ 2NH₃

128K