Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 13:34Z

F = ma

∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

263K

\lim_{β\to 0} \frac{\sin β}{β} = 1

∑_{k=1}^{n} k = n(n+1)/2

139K

CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

8ψ² + 7ψ + 0 = 0

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iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

439K

e^{i\pi} + 1 = 0

413K

1r² + 8r + 1 = 0

7t² + 1t + 0 = 0

e^{i\pi} + 1 = 0