Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z

11n² + 5n + 4 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

459K

8ψ² + 7ψ + 0 = 0

406K

∂y/∂n = 5y

181K

10ω² + 7ω + 4 = 0

80K