Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z

11n² + 5n + 4 = 0

PV = nRT

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

d/dt [t^3] = 3t^2

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8ψ² + 7ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

448K

det| 2 8 ; 7 3 | = -50

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∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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