Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z
det| 5 4 ; 6 6 | = 6
∑_{k=1}^{n} k = n(n+1)/2
438K
∇²φ = 0
∑_{k=1}^{n} k = n(n+1)/2
186K
det| 12 5 ; 4 13 | = 136
det| 7 4 ; 4 8 | = 40
22K
∑_{k=1}^{n} k = n(n+1)/2
CaCO₃ → CaO + CO₂
E = mc²
ω = 2πf