Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:50Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
∑_{k=1}^{n} k = n(n+1)/2
263K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 2 ; 6 5 | = 8
333K
det| 9 4 ; 1 10 | = 86
160K
∑_{k=1}^{n} k = n(n+1)/2
413K