Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

e^{i\pi} + 1 = 0

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

406K

d/dt [t^3] = 3t^2

181K

\oint_C \vec{F}\cdot d\vec{r} = 0

80K

10ω² + 7ω + 4 = 0

359K

8ψ² + 7ψ + 0 = 0

455K