Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:41Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

451K

10ω² + 7ω + 4 = 0

264K

det| 8 9 ; 3 9 | = 45

∑_{k=1}^{n} k = n(n+1)/2

297K

∇ × E = −∂B/∂t

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

iħ ∂ψ/∂t = Ĥψ

48K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

411K

8ψ² + 7ψ + 0 = 0

377K

∇²θ = 0

299K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

401K