Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:17Z

3γ² + 8γ + 4 = 0

det| 7 4 ; 4 8 | = 40

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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PV = nRT

∇ × E = −∂B/∂t

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∂β/∂β = 6β

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det| 1 9 ; 5 2 | = -43

\lim_{β\to 0} \frac{\sin β}{β} = 1

448K

F = G m₁m₂ / r²

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ω = 2πf

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∂γ/∂θ = 2γ

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∂n/∂ψ = 6n

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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