Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-21 10:00Z
6y² + 3y + 3 = 0
ΔS ≥ 0
∫₀^∞ e^(-α²) dα = √π / 2
2K
det| 4 5 ; 4 5 | = 0
det| 9 4 ; 1 10 | = 86
26K
iħ ∂ψ/∂t = Ĥψ
det| 11 5 ; 0 12 | = 132
209K
∂t/∂α = 6t
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
9t² + 6t + 4 = 0
2α² + 8α + 2 = 0