Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

PV = nRT

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 11 4 ; 5 12 | = 112

186K

d/dφ [φ^1] = 1φ^0

411K

4φ² + 6φ + 2 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

iħ ∂ψ/∂t = Ĥψ

181K

PV = nRT

80K

det| 7 9 ; 1 8 | = 47

359K

8ψ² + 7ψ + 0 = 0

455K