Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 09:59Z

∫₀^∞ e^(-z²) dz = √π / 2

d/dt [t^3] = 3t^2

195K

PV = nRT

262K

10ω² + 8ω + 0 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

∇ × E = −∂B/∂t

244K

2H₂ + O₂ → 2H₂O

iħ ∂ψ/∂t = Ĥψ

231K

2H₂ + O₂ → 2H₂O

26K

9r² + 6r + 7 = 0

∫₀^∞ e^(-α²) dα = √π / 2

209K

8ψ² + 7ψ + 0 = 0

331K

12θ² + 8θ + 7 = 0

det| 12 1 ; 5 13 | = 151

163K

10r² + 5r + 3 = 0

12γ² + 9γ + 7 = 0

5φ² + 3φ + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂