Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

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∇ × E = −∂B/∂t

411K

4φ² + 6φ + 2 = 0

10ω² + 7ω + 4 = 0

448K

det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 3 7 ; 2 4 | = -2

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det| 3 6 ; 0 4 | = 12

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10t² + 9t + 5 = 0

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