Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-17 22:38Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
246K
9ψ² + 4ψ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
d/dβ [β^6] = 6β^5
det| 6 1 ; 4 7 | = 38
\frac{6}{5} \sum_{i=1}^{n} i^{2}
det| 4 2 ; 6 5 | = 8
447K
det| 7 4 ; 4 8 | = 40
297K
11y² + 2y + 6 = 0
det| 10 3 ; 1 11 | = 107
2H₂ + O₂ → 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂