Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 21:50Z

E = mc²

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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6x² + 6x + 1 = 0

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e^{i\pi} + 1 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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N₂ + 3H₂ ⇌ 2NH₃

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iħ ∂ψ/∂t = Ĥψ

CH₄ + 2O₂ → CO₂ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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∂γ/∂θ = 2γ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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E = mc²

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