Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:52Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 5 3 ; 7 6 | = 9

186K

det| 2 8 ; 7 3 | = -50

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

F = G m₁m₂ / r²

406K

∫₀^∞ e^(-α²) dα = √π / 2

181K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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