Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²t = 0

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

F = G m₁m₂ / r²

406K

∇²ω = 0

det| 7 4 ; 4 8 | = 40

181K

det| 4 7 ; 2 5 | = 6

80K