Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:33Z

∇²t = 0

5φ² + 1φ + 1 = 0

460K

det| 7 4 ; 4 8 | = 40

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det| 6 4 ; 3 7 | = 30

PV = nRT

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det| 7 8 ; 4 8 | = 24

411K

ΔS ≥ 0

E = mc²

448K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

22K

1z² + 3z + 2 = 0

PV = nRT

459K

∇²z = 0

406K

7t² + 3t + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

∑_{k=1}^{n} k = n(n+1)/2

359K

∇ × E = −∂B/∂t

455K