Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

6t² + 6t + 4 = 0

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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2H₂ + O₂ → 2H₂O

iħ ∂ψ/∂t = Ĥψ

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∇²θ = 0

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det| 4 8 ; 0 5 | = 20

∫₀^∞ e^(-θ²) dθ = √π / 2

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CaCO₃ → CaO + CO₂

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det| 2 8 ; 7 3 | = -50

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det| 7 4 ; 4 8 | = 40

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