Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

F = G m₁m₂ / r²

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

186K

det| 12 1 ; 5 13 | = 151

411K

4φ² + 6φ + 2 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

PV = nRT

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

∇ × E = −∂B/∂t

359K

5z² + 8z + 3 = 0

455K