Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:00Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

8ψ² + 7ψ + 0 = 0

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

d/dφ [φ^1] = 1φ^0

448K

det| 5 9 ; 7 6 | = -33

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∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

det| 10 7 ; 3 11 | = 89

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0