Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z
det| 5 4 ; 6 6 | = 6
det| 9 4 ; 1 10 | = 86
460K
∇²φ = 0
∑_{k=1}^{n} k = n(n+1)/2
411K
det| 12 5 ; 4 13 | = 136
det| 7 9 ; 1 8 | = 47
448K
∑_{k=1}^{n} k = n(n+1)/2
22K
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
406K
CaCO₃ → CaO + CO₂
∑_{k=1}^{n} k = n(n+1)/2
181K
∑_{k=1}^{n} k = n(n+1)/2
80K
det| 11 5 ; 0 12 | = 132
359K
∑_{k=1}^{n} k = n(n+1)/2
455K