Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:24Z

e^{i\pi} + 1 = 0

det| 7 6 ; 1 8 | = 50

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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λ = h/p

\lim_{t\to 0} \frac{\sin t}{t} = 1

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iħ ∂ψ/∂t = Ĥψ

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det| 6 7 ; 7 7 | = -7

iħ ∂ψ/∂t = Ĥψ

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∇²t = 0

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∇²ψ = 0

∂y/∂γ = 8y

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∂y/∂n = 5y

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N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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8ψ² + 7ψ + 0 = 0

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