Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 16:24Z

∂ψ/∂φ = 6ψ

∑_{k=1}^{n} k = n(n+1)/2

451K

∑_{k=1}^{n} k = n(n+1)/2

264K

11ψ² + 2ψ + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

297K

det| 7 2 ; 7 8 | = 42

252K

λ = h/p

8ψ² + 7ψ + 0 = 0

48K

iħ ∂ψ/∂t = Ĥψ

411K

det| 3 7 ; 2 4 | = -2

377K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

299K

e^{i\pi} + 1 = 0

401K

∇ × E = −∂B/∂t

420K

d/dt [t^3] = 3t^2

109K