Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:37Z

11n² + 5n + 4 = 0

F = ma

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

11t² + 9t + 7 = 0

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

∇²t = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇²ω = 0

459K

iħ ∂ψ/∂t = Ĥψ

406K

det| 9 4 ; 1 10 | = 86

181K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

80K

F = G m₁m₂ / r²

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