Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:36Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
460K
∫₀^∞ e^(-t²) dt = √π / 2
438K
4y² + 7y + 7 = 0
det| 7 4 ; 4 8 | = 40
186K
det| 11 5 ; 0 12 | = 132
411K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
∑_{k=1}^{n} k = n(n+1)/2
406K