Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z

11n² + 5n + 4 = 0

det| 10 2 ; 3 11 | = 104

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

ΔS ≥ 0

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

det| 12 2 ; 2 13 | = 152

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

det| 9 4 ; 1 10 | = 86

359K

∇²θ = 0

455K