Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:33Z

det| 11 2 ; 2 12 | = 128

∇²γ = 0

460K

iħ ∂ψ/∂t = Ĥψ

438K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

3θ² + 7θ + 1 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

448K

8x² + 2x + 7 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 11 4 ; 5 12 | = 112

459K

det| 10 7 ; 3 11 | = 89

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O