Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 16:21Z

∂ψ/∂φ = 6ψ

∑_{k=1}^{n} k = n(n+1)/2

451K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

264K

11ψ² + 2ψ + 6 = 0

∇²z = 0

297K

det| 7 4 ; 4 8 | = 40

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λ = h/p

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

411K

\frac{9}{7} \sum_{i=1}^{n} i^{2}

E = mc²

377K

6n² + 7n + 6 = 0

299K

N₂ + 3H₂ ⇌ 2NH₃

401K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

420K

∑_{k=1}^{n} k = n(n+1)/2

109K