Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:02Z
det| 6 5 ; 4 7 | = 22
det| 5 3 ; 7 6 | = 9
460K
∇²φ = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
186K
∫₀^∞ e^(-t²) dt = √π / 2
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
F = ma
det| 3 7 ; 2 4 | = -2
459K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∇²γ = 0
1φ² + 4φ + 5 = 0