Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:36Z

det| 6 5 ; 4 7 | = 22

\lim_{r\to 0} \frac{\sin r}{r} = 1

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6ω² + 4ω + 4 = 0

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∇²φ = 0

∫₀^∞ e^(-ω²) dω = √π / 2

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

F = G m₁m₂ / r²

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det| 7 4 ; 4 8 | = 40

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F = ma

CH₄ + 2O₂ → CO₂ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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ΔS ≥ 0

e^{i\pi} + 1 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∇ × E = −∂B/∂t

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