Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²t = 0

186K

det| 3 6 ; 0 4 | = 12

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∂γ/∂θ = 2γ

459K

8ψ² + 7ψ + 0 = 0

406K

∇²ω = 0

d/dt [t^3] = 3t^2

181K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

80K